How many extra electrons does an object with a charge of −9.6×10−19-9.6 \times 10^{-19}−9.6×10−19 C have?
The total change in a system is constant
What will the charge of each sphere be after the spheres are touched together and removed?
Fe=kq1q2r2F_e = k\frac{q_1 q_2}{r^2} Fe=kr2q1q2
What shows the relationship between the electrostatics force and the distance?
Note: You can make a spreadsheet to help with the calculations
Field Lines point in the direction that a positive point charge would experience a force.
E=FeqE = \frac{F_e}{q} E=qFe
The work needed or energy required by moving a positive charge in an electric field
W=Fd=(qE)d=qV⏞EPE=mgh⏟PEg=12mv2W = Fd = (qE)d = \overbrace{qV}^{\textrm{EPE}} = \underbrace{mgh}_{\textrm{PEg}} = \frac{1}{2}mv^2 W=Fd=(qE)d=qVEPE=PEgmgh=21mv2
This is the potential energy difference per unit charge between two points.
V=WqV = \frac{W}{q} V=qW